document.write( "Question 625518: The sum of the digits of a two-digit counting number is 9. When the digits are reversed, the new number is 45 less than the original number. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #393610 by lwsshak3(11628)\"\" \"About 
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The sum of the digits of a two-digit counting number is 9. When the digits are reversed, the new number is 45 less than the original number. What is the original number?
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\n" ); document.write( "let u=units digit
\n" ); document.write( "let t=tens digit
\n" ); document.write( "u+t=9
\n" ); document.write( "u=9-t
\n" ); document.write( "original number: 10t+u
\n" ); document.write( "new number: 10u+t
\n" ); document.write( "..
\n" ); document.write( "10t+u=10u+t-45
\n" ); document.write( "10t+9-t=10(9-t)+t-45
\n" ); document.write( "10t+9-t=90-10t+t-45
\n" ); document.write( "10t+9-t=90-10t+t-45
\n" ); document.write( "18t=36
\n" ); document.write( "t=2
\n" ); document.write( "u=9-t=7
\n" ); document.write( "original number:27
\n" ); document.write( "new number: 72
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