document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57577>Question 57577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four times the sum of the first and third of three consecutive integers is one less than seven times the middle integer. Find the integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39359 by </B><A HREF=/tutors/aboutme.mpl?userid=phillv><B>phillv(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=phillv><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first integer =X<BR>\n" );
document.write( "Therefor the second integer =X+1<BR>\n" );
document.write( "and the third integer = X+2<BR>\n" );
document.write( "The resulting equation is: 4(X+(X+1))=7(X+2)-1\r<BR>\n" );
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document.write( "4(2X+1)=7X+14-1<BR>\n" );
document.write( "8X+4=7X+13<BR>\n" );
document.write( "8X-7X=13-4<BR>\n" );
document.write( "X=9<BR>\n" );
document.write( "The first integer is X=9<BR>\n" );
document.write( "The second integer is X+1=10<BR>\n" );
document.write( "The third integer is X+2=11 </SPAN>\n" );
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