document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625488>Question 625488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi my problem says: find three consecutive odd integers such that 7 times the sum of the first and the third is 120 less than 10 times the OPPOSITE of the second. <BR>\n" );
document.write( "Please show work :) thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393572 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"three consecutive odd integers such that 7 times the sum of the first and the third is 120 less than 10 times the OPPOSITE of the second\" translates to \r<BR>\n" );
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document.write( "7*( (2x+1) + (2x+5) ) = 10(-1(2x+3)) - 120\r<BR>\n" );
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document.write( "This is because 2x+1 is an odd integer, 2x+3 is the next consecutive odd integer, and 2x+5 is the next consecutive odd integer after that\r<BR>\n" );
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document.write( "Let's solve for x\r<BR>\n" );
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document.write( "7*( (2x+1) + (2x+5) ) = 10(-1(2x+3)) - 120\r<BR>\n" );
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document.write( "7*( (2x+1) + (2x+5) ) = -10(2x+3) - 120\r<BR>\n" );
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document.write( "7*( 2x+1 + 2x+5 ) = -10(2x+3) - 120\r<BR>\n" );
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document.write( "7*( 4x+6 ) = -10(2x+3) - 120\r<BR>\n" );
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document.write( "28x+42 = -20x - 30 - 120\r<BR>\n" );
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document.write( "28x+42 = -20x - 150\r<BR>\n" );
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document.write( "28x+20x = -150-42\r<BR>\n" );
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document.write( "48x = -192\r<BR>\n" );
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document.write( "x = -192/48\r<BR>\n" );
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document.write( "x = -4\r<BR>\n" );
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document.write( "Now that we know that x = -4, we can plug it into 2x+1, 2x+3, and 2x+5 to find the three consecutive odd integers\r<BR>\n" );
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document.write( "2x+1 = 2(-4)+1 = -7\r<BR>\n" );
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document.write( "2x+3 = 2(-4)+3 = -5\r<BR>\n" );
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document.write( "2x+5 = 2(-4)+5 = -3\r<BR>\n" );
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document.write( "So the three  consecutive odd integers are -7, -5, and -3\r<BR>\n" );
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