document.write( "Question 57585This question is from textbook Elementary and Intermediate Algebra
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document.write( "Fawn invested a certain amount of money at 3% interest and $1250 more than that amount at 5%. Her total yearly interest was $134.50. How much did she invest at each rate? \n" );
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Algebra.Com's Answer #39353 by phillv(13)![]() ![]() ![]() You can put this solution on YOUR website! Let X be the amount invested at 3%. \n" ); document.write( "Let X+1250 be the amount invested at 5%. \n" ); document.write( "134.50=.03X+(X+1250)(.05) \n" ); document.write( "134.50=.03X + .05X + 62.50 \n" ); document.write( "134.50=.08X + 62.50 \n" ); document.write( "72.00=.08X \n" ); document.write( "X=72.00/.08 \n" ); document.write( "X=900.00 \n" ); document.write( "$900.00 was the amount invested at 3% \n" ); document.write( "$900.00 + $1250.00 = $2,150.00 was the amount invested at 5%. \n" ); document.write( " |