document.write( "Question 625360: Find the consecutive numbers such that one- third the greater number exceeds one- fifth of the lesser number by 7.\r
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Algebra.Com's Answer #393506 by reynard2007(52) $\"\"$ $\"About$

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\n" ); document.write( "Let (x+1) and (x) be the consecutive numbers. We get one-thir of the bigger number by addin 7 to one-fifth of the smaller.
\n" ); document.write( " $\"%281%2F3%29%28x%2B1%29=%281%2F5%29x%2B7\"$
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\n" ); document.write( "To get rid of the fractions, we multiply both sides of the equation by their LCD, 15. We get:
\n" ); document.write( " $\"5%28x%2B1%29=3x%2B+105\"$
\n" ); document.write( " $\"5x%2B5=3x%2B105\"$
\n" ); document.write( " $\"2x=100\"$
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\n" ); document.write( "The consecutive numbers are 50 and 51. Just check the answer aainst the problem and tell me what happens. :D \n" ); document.write( "

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