document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625390>Question 625390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Palmyra Triangle has a perimeter of 4800 miles. The side of middle length is 3 times as long as the shortest side. The longest side is 4 times as long as the middle side. How long is each side?<BR>\n" );
document.write( "The shortest side is ___ miles long. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393503 by </B><A HREF=/tutors/aboutme.mpl?userid=reynard2007><B>reynard2007(52)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reynard2007><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reynard2007><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=calibri size=3>\r<BR>\n" );
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document.write( "The perimeter of a rectangle is the sum of twice the length and twice the width. In algebraic form, here it is:<BR>\n" );
document.write( "Perimeter = 2L + 2W<BR>\n" );
document.write( "If the length is 80 more than the width, then we just substitute l with W+80:<BR>\n" );
document.write( "Perimeter = 2(W+80) + 2W = 200<BR>\n" );
document.write( "2W + 160 + 2W = 200<BR>\n" );
document.write( "4W = 200 - 160 = 40<BR>\n" );
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document.write( "<tr><TD >W = 10 yards<BR>\n" );
document.write( "L = 90 yards</TD></tr>\n" );
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