document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57634>Question 57634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a) Solve the following equation\r<BR>\n" );
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document.write( "0.5x+0.2(x-20)=0.3x+6\r<BR>\n" );
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document.write( "b)Solve the following equation\r<BR>\n" );
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document.write( "2/3x+1/5x=x-5/12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39350 by </B><A HREF=/tutors/aboutme.mpl?userid=Garree10><B>Garree10(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Garree10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.5x+0.2(x-20)=0.3x+6   times 2with -20=-4<BR>\n" );
document.write( "0.5x+0.2x-4=0.3x+6<BR>\n" );
document.write( "-0.2 -0.2<BR>\n" );
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document.write( " 0.3x-4=0.3x +6    </SPAN>\n" );
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