document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625348>Question 625348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle has its center at the center of a square with 12-inch sides. Using 3.14 for pi, find the area of the square not covered by the circle, then write a ratio of the circle’s circumference to the perimeter of the square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393474 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A circle has its center at the center of a square with 12-inch sides. Using 3.14 for pi, find the area of the square not covered by the circle<BR>\n" );
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document.write( "Area of the square = 12*12 = 144 sq inches<BR>\n" );
document.write( "Area of the circle = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2+=+36pi ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2+=+36pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq inches<BR>\n" );
document.write( "--> 144 - 36pi sq inches<BR>\n" );
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document.write( " then write a ratio of the circle’s circumference to the perimeter of the square.<BR>\n" );
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document.write( "Sq P = 4*12 = 48<BR>\n" );
document.write( "C = 2*pi*r = 12pi<BR>\n" );
document.write( "--> 12pi/48<BR>\n" );
document.write( "= pi/4<BR>\n" );
document.write( " </SPAN>\n" );
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