document.write( "Question 625312: There are 27 nickels, dimes, and quarters in the drawer with a value of $3. How many coins of each type are there if there are three times as many nickels as there are dimes? \n" ); document.write( "
Algebra.Com's Answer #393430 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "There are 27 nickels, dimes, and quarters in the drawer with a value of $3. How many coins of each type are there if there are three times as many nickels as there are dimes?\r
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\n" ); document.write( "\n" ); document.write( "Let amount of nickels, dimes, and quarters be N, D, and Q, respectively\r
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\n" ); document.write( "\n" ); document.write( "Then: N + D + Q = 27\r
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\n" ); document.write( "\n" ); document.write( "Also, N = 3D, since there are 3 times as many nickels as dimes\r
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\n" ); document.write( "\n" ); document.write( "Substituting 3D for N, we now have: 3D + D + Q = 27, or 4D + Q = 27 ----- eq (i)\r
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\n" ); document.write( "\n" ); document.write( "Also, .05(3D) + .1(D) + .25(Q) = 3 ---- .15D + .1D + .25Q = 3 ---- .25D + .25Q = 3 ---- eq (ii)\r
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\n" ); document.write( "\n" ); document.write( "4D + Q = 27 ----- eq (i)
\n" ); document.write( "- 4D - 4Q = - 48 ---- Multiplying eq (ii) by - 16 ----- eq (iii)
\n" ); document.write( "- 3Q = - 21 ------ Adding eqs (iii) & (i)\r
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\n" ); document.write( "\n" ); document.write( "Q, or amount of quarters = \"%28-+21%29%2F-+3\", or \"highlight_green%287%29\"\r
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\n" ); document.write( "\n" ); document.write( "4D + 7 = 27 ------ Substituting 7 for Q in eq (i)\r
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\n" ); document.write( "\n" ); document.write( "4D = 20\r
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\n" ); document.write( "\n" ); document.write( "D, or amount of dimes = \"20%2F4\", or \"highlight_green%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since there are 5 dimes, then there are 3 * 5, or \"highlight_green%2815%29\" nickels\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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