document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625270>Question 625270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Johen is hulf his father's age now. Fifteen years ago,he was one-third of his father's age. How old wil johe be after 5 year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393417 by </B><A HREF=/tutors/aboutme.mpl?userid=jankiz><B>jankiz(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jankiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jankiz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can set up an equation like this: 1/2x-15=1/3x. Add 15, subtract 1/3x and you get 1/6x=15. Multiply by 6, you get x=90. One half of 90 is 45. Subtract 15 from 45, you get thirty. Five years later, he will be 35. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );