document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625312>Question 625312</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are 27 nickels, dimes, and quarters in the drawer with a value of $3. How many coins of each type are there if there are three times as many nickels as there are dimes? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393416 by </B><A HREF=/tutors/aboutme.mpl?userid=jankiz><B>jankiz(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jankiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jankiz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you have 27 nickels, and that is 3 times more than dimes, you divide 27 by three. Then you get 9 dimes. Then, multiply 27 by 5 to get the value of nickels, wich is $1.35.  Then 9*10 to get the value of dimes, which is 90 cent. Then you add 1.35 to .90 cent, and get 2.25.  So you need 75 cents more, which equals 3 quarters. In conclusion, you need 27 nickels, 9 dimes, and 3 quarters! </SPAN>\n" );
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