document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625263>Question 625263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary angles if the sum of their measures is 180.  Find two supplementary angles such that the measure of the first angle is 54 less than three times the measure of the second </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393401 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+3x-54=180<BR>\n" );
document.write( "4x=180+54<BR>\n" );
document.write( "4x=234<BR>\n" );
document.write( "x=234/4<BR>\n" );
document.write( "x=58.5<BR>\n" );
document.write( "3x-54=121.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );