document.write( "Question 625229: How many liters of a 50% acid solution must be added to 10 liters of a 15% acid solution to produce a 25% acid solution? \n" ); document.write( "
Algebra.Com's Answer #393389 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = liters of 50% acid solution needed
\n" ); document.write( "\"+.5x+\" = liters of acid in 50% solution
\n" ); document.write( "\"+.15%2A10+=+1.5+\" liters of acid in 15% solution
\n" ); document.write( "-----------
\n" ); document.write( "\"+%28+.5x+%2B+1.5+%29+%2F+%28+x+%2B+10+%29+=+.25+\"
\n" ); document.write( "\"+.5x+%2B+1.5+=+.25%2A%28+x+%2B+10+%29+\"
\n" ); document.write( "\"+.5x+%2B+1.5+=+.25x+%2B+2.5+\"
\n" ); document.write( "\"+.25x+=+2.5+-+1.5+\"
\n" ); document.write( "\"+.25x+=+1+\"
\n" ); document.write( "\"+x+=+4+\"
\n" ); document.write( "4 liters of 50% acid solution are needed
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+.5x+%2B+1.5+%29+%2F+%28+x+%2B+10+%29+=+.25+\"
\n" ); document.write( "\"+%28+.5%2A4+%2B+1.5+%29+%2F+%28+4+%2B+10+%29+=+.25+\"
\n" ); document.write( "\"+3.5+%2F+14+=+.25+\"
\n" ); document.write( "\"+3.5+=+.25%2A14+\"
\n" ); document.write( "\"+3.5+=+3.5+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );