document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625037>Question 625037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of the line passing through point (4,-1) and parallel to the line joining A(-2,5) and B(4,9)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393368 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> slope of the line AB where A(-2,5) and B(4,9)  is (9-5)/(4+2) = 4/6 = 2/3\r<BR>\n" );
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document.write( "y = (2/3)x+b\r<BR>\n" );
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document.write( "Since (4,-1) is in the line:\r<BR>\n" );
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document.write( "-1 = (2/3)4+b\r<BR>\n" );
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document.write( "b = -1 -8/3\r<BR>\n" );
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document.write( "b = -11/3\r<BR>\n" );
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document.write( "Answer: y = (2/3)x -11/3\r<BR>\n" );
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document.write( "If you have any doubt or if you have  more problems my e-mail is:  \r<BR>\n" );
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document.write( "mthman@gmail.com </SPAN>\n" );
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