document.write( "Question 625141: One zero of the function is -4, find the others.
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document.write( "f(x)=x^3-2x^2-11x+52 \n" );
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Algebra.Com's Answer #393330 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! f(x)=x^3-2x^2-11x+52\r \n" ); document.write( "\n" ); document.write( " 1 -2 -11 52\r \n" ); document.write( "\n" ); document.write( "-4 -4 24 -52\r \n" ); document.write( "\n" ); document.write( " 1 -6 13 0\r \n" ); document.write( "\n" ); document.write( "x^2-6x+13 =0\r \n" ); document.write( "\n" ); document.write( "x = [6 +- sqrt(-16)]/2\r \n" ); document.write( "\n" ); document.write( "= [6+-4i]/2\r \n" ); document.write( "\n" ); document.write( "3+-2i\r \n" ); document.write( "\n" ); document.write( "Answer: remaining zeros are: 3+2i and 3-2i\r \n" ); document.write( "\n" ); document.write( "If you have any doubt or if you have more problems my e-mail is: \r \n" ); document.write( "\n" ); document.write( "mthman@gmail.com\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |