document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625140>Question 625140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the tens digit of a 2 digit no. is 2 times its ones digit. if the digits are reversed,the sum of the original no. and the no. so formed is 66.find the number.    .........................................help me plz i am stuck thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393329 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Letthe number = \"ab\"\r<BR>\n" );
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document.write( "a = 2b\r<BR>\n" );
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document.write( "10a+b + 10b+a = 66\r<BR>\n" );
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document.write( "11(a+b)= 66\r<BR>\n" );
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document.write( "a+b = 6\r<BR>\n" );
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document.write( "Then:\r<BR>\n" );
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document.write( "2b+b=6\r<BR>\n" );
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document.write( "3b=6\r<BR>\n" );
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document.write( "b = 2\r<BR>\n" );
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document.write( "a = 4\r<BR>\n" );
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document.write( "Answer: the number is 42\r<BR>\n" );
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document.write( "If you have any doubt or if you have  more problems my e-mail is:  \r<BR>\n" );
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document.write( "mthman@gmail.com\r<BR>\n" );
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document.write( " </SPAN>\n" );
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