document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625016>Question 625016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 30ft. The length is 11 ft longer than width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393289 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393289\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Per = 2(x+y)=30\r<BR>\n" );
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document.write( "x = y+11\r<BR>\n" );
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document.write( "Then:\r<BR>\n" );
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document.write( "2(y+11+y)=30\r<BR>\n" );
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document.write( "2y+11=15\r<BR>\n" );
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document.write( "2y=4\r<BR>\n" );
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document.write( "y=2\r<BR>\n" );
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document.write( "x=13\r<BR>\n" );
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document.write( "Answer: Width = 2 and Lenght= 13\r<BR>\n" );
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document.write( "If you have any doubt or if you have  more problems my e-mail is:  \r<BR>\n" );
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document.write( "mthman@gmail.com\r<BR>\n" );
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document.write( "Answer: </SPAN>\n" );
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