document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=624953>Question 624953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Keri's Saturday morning jog follows a triangular path. Two legs of the path are equal, and the third leg is 4 miles shorter than each of the other legs. If the total path is 14 miles long find the length of the third leg of the triangular path. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393235 by </B><A HREF=/tutors/aboutme.mpl?userid=jankiz><B>jankiz(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jankiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jankiz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, you draw a triangle.  Then you lable each equal leg x and the third leg x-4.  Then you combine the x's.  So, x+x+x-4=14.  Then solve for x.  3x=18. So, x is 6.  Then, you put 6 pack in to the triangle.  So, the third leg equals 2, because 6-4!   </SPAN>\n" );
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