document.write( "Question 625022: Please help me with the following equation: \r
\n" ); document.write( "\n" ); document.write( "1. Carolyn received a check last week. She invested part at 15%and $1000 more than this at 16%. If she will earn $780 in interest in a year, how much was invested at each rate? \r
\n" ); document.write( "\n" ); document.write( "This is what I have so far:
\n" ); document.write( "I=PRT\r
\n" ); document.write( "\n" ); document.write( "x= first investment
\n" ); document.write( "x+1000 second investment
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #393234 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
1. Carolyn received a check last week. She invested part at 15%and $1000 more than this at 16%. If she will earn $780 in interest in a year, how much was invested at each rate? \r
\n" ); document.write( "\n" ); document.write( "This is what I have so far:
\n" ); document.write( "I=PRT\r
\n" ); document.write( "\n" ); document.write( "x= first investment
\n" ); document.write( "x+1000 second investment
\n" ); document.write( "-------------
\n" ); document.write( "You can do it that way.
\n" ); document.write( "Then,
\n" ); document.write( "0.15x + 0.16(x+1000) = 780
\n" ); document.write( "0.31x + 160 = 780
\n" ); document.write( "x = 2000
\n" ); document.write( "----------
\n" ); document.write( "$2000 @ 15%
\n" ); document.write( "$3000 @ 16%
\n" ); document.write( " \n" ); document.write( "
\n" );