document.write( "Question 624976: let me re-write the question which two tutors could not understand because of the student not using a proper notation, even it was more or less obvious what he meant:
\n" ); document.write( "Question 624950:
\n" ); document.write( "If cos= 2 to the square root of 10/7 calculate the value of sin.\r
\n" ); document.write( "\n" ); document.write( "Should be posted this way:
\n" ); document.write( "If cos = (2 x sq.root(10))/7 calculate the value of sin. (answer is a.)\r
\n" ); document.write( "\n" ); document.write( "a. 3/7
\n" ); document.write( "b. square root of 29/7
\n" ); document.write( "c. square root of 69/7
\n" ); document.write( "d. square root of 89/7
\n" ); document.write( "Found 2 solutions by Alan3354, jsmallt9:
\n" ); document.write( "

Algebra.Com's Answer #393220 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
let me re-write the question which two tutors could not understand because of the student not using a proper notation, even it was more or less obvious what he meant:
\n" ); document.write( "Question 624950:
\n" ); document.write( "If cos= 2 to the square root of 10/7 calculate the value of sin.\r
\n" ); document.write( "\n" ); document.write( "Should be posted this way:
\n" ); document.write( "If cos = (2 x sq.root(10))/7 calculate the value of sin. (answer is a.)\r
\n" ); document.write( "\n" ); document.write( "a. 3/7
\n" ); document.write( "b. square root of 29/7
\n" ); document.write( "c. square root of 69/7
\n" ); document.write( "d. square root of 89/7
\n" ); document.write( "Found 2 solutions by Alan3354, jsmallt9:
\n" ); document.write( "-------------
\n" ); document.write( "The only thing obvious about it was that it made no sense.
\n" ); document.write( "Part of education is learning how to make sense, not speak gibberish.
\n" ); document.write( "---------
\n" ); document.write( "\"cos%28x%29+=+2sqrt%2810%29%2F7\"
\n" ); document.write( "\"sin%28x%29+=+sqrt%281+-+cos%5E2%28x%29%29\"
\n" ); document.write( "\"sin%28x%29+=+sqrt%28+1+-+40%2F49%29+=+sqrt%289%2F49%29\"
\n" ); document.write( "sin = 3/7 (principal value)
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\n" ); document.write( "
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