document.write( "Question 624864: The perimeter of the rectangle is 46m. If the width were doubled and the length were increased by 5m, the perimeter would be 66m. What is the length of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #393187 by lwsshak3(11628)\"\" \"About 
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The perimeter of the rectangle is 46m. If the width were doubled and the length were increased by 5m, the perimeter would be 66m. What is the length of the original rectangle?
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\n" ); document.write( "let x=length of original triangle
\n" ); document.write( "let y=width of original triangle
\n" ); document.write( "2y+2x=perimeter=46
\n" ); document.write( "x+y=23
\n" ); document.write( "y=23-x
\n" ); document.write( "..
\n" ); document.write( "2y+x+5=66
\n" ); document.write( "2(23-x)+x+5=66
\n" ); document.write( "46-2x+x+5=66
\n" ); document.write( "x=15
\n" ); document.write( "y=23-15=8
\n" ); document.write( "length of original triangle=15 m
\n" ); document.write( "width of original triangle=8 m
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