document.write( "Question 7128: ((2x-14)/2x)*((6x^2)/X^2-49))=\r
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document.write( "I have broken the question down to:
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document.write( "((2(x-7)/2x))*((3x*3x)/(x(x-49))
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document.write( "and this is where I am lost..... \n" );
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Algebra.Com's Answer #3931 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let's see:\r \n" ); document.write( "\n" ); document.write( "Simplify: \n" ); document.write( "\n" ); document.write( "Your first step was ok, factor out the 2 in the first fraction. The second part was not quite right. In the second fraction, you can factor the binomial in the denominator: \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the first fraction, cancel the 2's, then cancel the (x-7)'s, finally, cancel an x from the denominator of the first fraction and the numerator of the second fraction.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |