document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=624830>Question 624830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jury pool consists of 25 people. How many different juries consisting of 12 people are possible? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393088 by </B><A HREF=/tutors/aboutme.mpl?userid=reynard2007><B>reynard2007(52)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reynard2007><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reynard2007><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a simple problem. You only have to know if you will use permutation or combination. But, since position in a sequence does not matter here -- like who comes first or second -- we shall use  combination.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=25C12=+25%21%2F%28%2825-12%29%21%2812%21%29%29+=+5%2C200%2C300+ ALIGN=MIDDLE  ALT=\"25C12=+25%21%2F%28%2825-12%29%21%2812%21%29%29+=+5%2C200%2C300+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You can choose a jury in<b> 5,200,300</b> ways. </SPAN>\n" );
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