document.write( "Question 57583This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": To Whomever can assist... Thanks!\r
\n" ); document.write( "\n" ); document.write( "Nina received an inheritance of $12,000 from her grandmother. She invested part of it at 6% interest and the remainder at 8%. If the total yearly interest from both investments was $860, how much did she invest at each rate?
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Algebra.Com's Answer #39302 by rcmcc(152)\"\" \"About 
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we can solve this question by setting up a linear equation,\r
\n" ); document.write( "\n" ); document.write( "let x be investment 1
\n" ); document.write( "let y be investment 2\r
\n" ); document.write( "\n" ); document.write( "because both investments x and y add up to 12000 we can state\r
\n" ); document.write( "\n" ); document.write( "x+y=12000\r
\n" ); document.write( "\n" ); document.write( "because the interest on x is 6% and y is 8% and the total interest earned is 860 we can state\r
\n" ); document.write( "\n" ); document.write( "0.06X+0.08Y=860...we have to convert the percent to a decimal\r
\n" ); document.write( "\n" ); document.write( "so these are your 2 equations.
\n" ); document.write( "x+y=12000
\n" ); document.write( "0.06X+0.08Y=860
\n" ); document.write( "to solve for y we must multiply the top equation by .06 \r
\n" ); document.write( "\n" ); document.write( ".06X+.06Y=720\r
\n" ); document.write( "\n" ); document.write( "subtract the bottom equation from the top equation to leave y in a single equation.
\n" ); document.write( ".06X+.06Y=720
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\n" ); document.write( "0.06X+0.08Y=860
\n" ); document.write( "so
\n" ); document.write( "-.02Y=-140
\n" ); document.write( "multiply by -1 to make them positive numbers
\n" ); document.write( ".02Y=140
\n" ); document.write( "now divide by .02 to each sides to isolate y\r
\n" ); document.write( "\n" ); document.write( "y=7000\r
\n" ); document.write( "\n" ); document.write( "solve for x by placing y into the first equation\r
\n" ); document.write( "\n" ); document.write( "x+7000=12000
\n" ); document.write( "subtract 7000
\n" ); document.write( "x=5000.\r
\n" ); document.write( "\n" ); document.write( "so nina invested $5000 at 6% interest and 7000 at 8% interest
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