document.write( "Question 624676: Solve cosec 2θ=secθ+cotθ \n" ); document.write( "
Algebra.Com's Answer #393000 by Alan3354(69443)\"\" \"About 
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Solve cosec 2θ=secθ+cotθ
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\n" ); document.write( "csc(2t) = sec(t) + cot(t)
\n" ); document.write( "1/sin(2t) = 1/cos(t) + cos(t)/sin(t)
\n" ); document.write( "1/(2sin*cos) = 1/cos + cos/sin
\n" ); document.write( "1/2 = sin + cos^2
\n" ); document.write( "1/2 = sin + (1 - sin^2)
\n" ); document.write( "2sin^2 - 2sin - 1 = 0
\n" ); document.write( "2x^2 - 2x - 1 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"2x%5E2%2B2x%2B-1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A2%2A-1=12\".
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\n" ); document.write( " Discriminant d=12 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+12+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%282%29%2Bsqrt%28+12+%29%29%2F2%5C2+=+0.366025403784439\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%282%29-sqrt%28+12+%29%29%2F2%5C2+=+-1.36602540378444\"
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\n" ); document.write( " Quadratic expression \"2x%5E2%2B2x%2B-1\" can be factored:
\n" ); document.write( " \"2x%5E2%2B2x%2B-1+=+%28x-0.366025403784439%29%2A%28x--1.36602540378444%29\"
\n" ); document.write( " Again, the answer is: 0.366025403784439, -1.36602540378444.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B2%2Ax%2B-1+%29\"

\n" ); document.write( "\n" ); document.write( "sin(t) = x =~ 0.36603
\n" ); document.write( "theta =~ 21.47 degs (principal value)\r
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