document.write( "Question 57579This question is from textbook Elementary and Intermediate Algebra
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\n" ); document.write( "\n" ); document.write( "A tank contains 50 gallons of a 40% solution of antifreeze. How much solution needs to be drained out and replaced with pure antifreeze to obtain a 50% solution?
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Algebra.Com's Answer #39300 by funmath(2933)\"\" \"About 
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A tank contains 50 gallons of a 40% solution of antifreeze. How much solution needs to be drained out and replaced with pure antifreeze to obtain a 50% solution?
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\n" ); document.write( "Let the unknown amount of solution be: x
\n" ); document.write( "You start out with: .40(50)
\n" ); document.write( "you take out: .40x
\n" ); document.write( "You put in: 1.00x
\n" ); document.write( "Then you get: .50(50)
\n" ); document.write( "The equation to solve is:
\n" ); document.write( ".40(50)-.40x+1.00x=.50(50)
\n" ); document.write( "20-.40x+1.00x=25
\n" ); document.write( "20+.60x=25
\n" ); document.write( "20-20+.60x=25-20
\n" ); document.write( ".60x=5
\n" ); document.write( ".60x/.60=5/.60
\n" ); document.write( "x=8.33 gal
\n" ); document.write( "Happy Calculating!!!
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