document.write( "Question 624733: Car 1 leaves point A at 5:30 pm, driving due south at an average speed of 35 mph. Car 2 leaves point A at 6:30 pm, driving due north at an average speed of 45 mph. How far apart will the drivers be at 9:30 pm? \n" ); document.write( "

Algebra.Com's Answer #392990 by Edwin McCravy(20055) $\"\"$ $\"About$

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Car 1 leaves point A at 5:30 pm, driving due south at an average speed of 35 mph. Car 2 leaves point A at 6:30 pm, driving due north at an average speed of 45 mph. How far apart will the drivers be at 9:30 pm?
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document.write( "When car 2 leaves at 6:30, 1 hour after Car 1, Car 1 is 35 miles from Car 2.\r\n" );
document.write( "They then are separating at the rate of 35mph+45mph or 80mph, so after \r\n" );
document.write( "3 hours, at 9:30 they will have separated an additional 3×80 = 240 miles. So\r\n" );
document.write( "they will be 35+240 or 275 miles apart at 9:30.\r\n" );
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document.write( "Edwin

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