document.write( "Question 57584: how do i find three consecutive intergers such that the sum of the squares is 77. \n" ); document.write( "

Algebra.Com's Answer #39297 by stanbon(75887) $\"\"$ $\"About$

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how do i find three consecutive intergers such that the sum of the squares is 77.
\n" ); document.write( "Let the consecutive integers be x, x+1, x+2.
\n" ); document.write( "EQUATION:
\n" ); document.write( "x^2+(x^1)^2+(x+2)^2=77
\n" ); document.write( "x^2+x^2+2x+1 + x^2+4x+2=77
\n" ); document.write( "3x^2+6x+3=77
\n" ); document.write( "3x^2+6x-74=0
\n" ); document.write( "x=[-6+-sqrt(6^2-4*3*-74)]/6
\n" ); document.write( "x=[-6+-sqrt(924)]/6
\n" ); document.write( "Comment: This answer is not an integer.
\n" ); document.write( "There are no consecutive integers that meet
\n" ); document.write( "the requirement of the equation.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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