document.write( "Question 624668: If a mother is three times older than her daughter and in twelve years she is twice oldes than the daughter, whats the mother age now? \n" ); document.write( "
Algebra.Com's Answer #392942 by oscargut(2103)\"\" \"About 
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If a mother is three times older than her daughter and in twelve years she is twice oldes than the daughter, whats the mother age now?\r
\n" ); document.write( "\n" ); document.write( "Solution:\r
\n" ); document.write( "\n" ); document.write( "Let x = Mother´s age now\r
\n" ); document.write( "\n" ); document.write( "Let y = Daughter´s age now\r
\n" ); document.write( "\n" ); document.write( "x = 3y (1)\r
\n" ); document.write( "\n" ); document.write( "(x+12)= 2(y+12)(2)\r
\n" ); document.write( "\n" ); document.write( "Then:\r
\n" ); document.write( "\n" ); document.write( "3y+12 = 2y+24\r
\n" ); document.write( "\n" ); document.write( "3y-2y = 24-12\r
\n" ); document.write( "\n" ); document.write( "y = 12\r
\n" ); document.write( "\n" ); document.write( "x = 3y =3(12)=36\r
\n" ); document.write( "\n" ); document.write( "Answer: 36 years\r
\n" ); document.write( "\n" ); document.write( "You can visit my page: http://maths2012.webs.com\r
\n" ); document.write( "\n" ); document.write( "Or you can send me more problems to my e-mail: mthman@gmail.com\r
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