document.write( "Question 624635: Two trains run on same track and at rates 25 and 30 mph. If the slower trains starts 1 hour earlier how long will it take the for the faster train to catch up?
\n" ); document.write( "I can solve this problem by\r
\n" ); document.write( "\n" ); document.write( "Slow 25 (x+1)
\n" ); document.write( "Fast 30 (x) 25x+25=30x -------- x =5
\n" ); document.write( "My questions is why can’t you solve it this way\r
\n" ); document.write( "\n" ); document.write( "Slow 25 (x)
\n" ); document.write( "Fast 30 (x-1) ----x=6 ??????????????????????????????
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Algebra.Com's Answer #392918 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Two trains run on same track and at rates 25 and 30 mph. If the slower trains starts 1 hour earlier how long will it take the for the faster train to catch up?
\n" ); document.write( "I can solve this problem by\r
\n" ); document.write( "\n" ); document.write( "Slow 25 (x+1)
\n" ); document.write( "Fast 30 (x) 25x+25=30x -------- x =5
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\n" ); document.write( "My questions is why can’t you solve it this way\r
\n" ); document.write( "\n" ); document.write( "Slow 25 (x)
\n" ); document.write( "Fast 30 (x-1) ----x=6 ??????????????????????????????
\n" ); document.write( "----------------
\n" ); document.write( "Multiplying x-1 times 30 gives a headstart of 30 miles, not 25.
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\n" ); document.write( "Do it like this.
\n" ); document.write( "The 1st train is 25 miles away when the 2nd starts.
\n" ); document.write( "The 2nd gains in the 1st at 5 mi/hr (a better statement is the speed of the 2nd wrt to the 1st is 5 mi/hr, since all motion is relative)
\n" ); document.write( "25/5 = 5 hours.
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