document.write( "Question 624573: My teacher just started doing this with me can someone help me out. \r
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\n" ); document.write( "\n" ); document.write( "A rectangle has an area of 240 {cm}^2 and a perimeter of 64 cm. What are its dimensions? Need to find the length and the with
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Algebra.Com's Answer #392860 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
A rectangle has an area of 240 {cm}^2 and a perimeter of 64 cm. What are its dimensions? Need to find the length and the width
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\n" ); document.write( "let x=length
\n" ); document.write( "let y=width
\n" ); document.write( "Area of a rectangle=length*width=xy
\n" ); document.write( "Perimeter=twice the length+twice the width=2x+2y
\n" ); document.write( "64=2x+2y
\n" ); document.write( "32=x+y
\n" ); document.write( "y=32-x
\n" ); document.write( "..
\n" ); document.write( "240=x*y=x(32-x)=32x-x^2
\n" ); document.write( "x^2-32x+240=0
\n" ); document.write( "(x-12)(x-20)=0
\n" ); document.write( "x=12(reject, x=length)
\n" ); document.write( "or
\n" ); document.write( "x=20
\n" ); document.write( "32-x=12
\n" ); document.write( "Dimensions of rectangle:
\n" ); document.write( "length=20 cm
\n" ); document.write( "width=12 cm
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