document.write( "Question 624523: solve the equation 9 log5 x = 25 logx 5, expressing your answers in the form 5^p/q, where p, and q are integers \n" ); document.write( "
Algebra.Com's Answer #392823 by Theo(13342) You can put this solution on YOUR website! original equation to be solved is: \n" ); document.write( "9*log(5,x) = 25*log(x,5) \n" ); document.write( "log(5,x) means log of x to the base of 5. \n" ); document.write( "log(x,5) means log of 5 to the base of x. \n" ); document.write( "convert everything to base of 5 using the base conversion formula of log(b,x) = log(c,x)/log(c,b). \n" ); document.write( "original equation of 9*log(5,x) = 25*log(x,5) becomes: \n" ); document.write( "9*log(5,x) = 25*log(5,5)/log(5,x) \n" ); document.write( "since log(5,5) is equal to 1, this equation becomes: \n" ); document.write( "9*log(5,x) = 25/log(5,x) \n" ); document.write( "multiply both sides of this equation by log(5,x) and divide both sides of this equation by 9 to get: \n" ); document.write( "log(5,x) * log(5,x) = 25/9 \n" ); document.write( "this can be written as: \n" ); document.write( "(log(5,x))^2 = 25/9 \n" ); document.write( "take the square root of both sides of this equation to get: \n" ); document.write( "log(5,x) = +/- sqrt(25/9) which becomes: \n" ); document.write( "log(5,x) = +/- 5/3 \n" ); document.write( "your possible answers are: \n" ); document.write( "log(5,x) = 5/3 \n" ); document.write( "log(5,x) = -5/3 \n" ); document.write( "from the basic definition of logarithms, you get: \n" ); document.write( "log(b,x) = c if and only if b^c = x \n" ); document.write( "apply this to your first possible answer and you get: \n" ); document.write( "log(5,x) = 5/3 if and only if 5^(5/3) = x \n" ); document.write( "that's one of your possible answers. \n" ); document.write( "x = 5^(5/3) \n" ); document.write( "apply this to your second possible answer and you get: \n" ); document.write( "log(5,x) = -5/3 if and only if 5^(-5/3) = x \n" ); document.write( "that's the other of your possible answers. \n" ); document.write( "5^(5/3) resolves to 14.62008869 \n" ); document.write( "5^-(5/3) resolves to 1/5^(5/3) which resolves to .068399038 \n" ); document.write( "to see if these answers are good, you need to substitute them into your original equation by substituting them in place of x. \n" ); document.write( "before you do that, however, you need to convert equation to base of 10 so you can solve it using your calculator. \n" ); document.write( "your original equation of: \n" ); document.write( "9*log(5,x) = 25*log(x,5) becomes: \n" ); document.write( "9*LOG(x)/LOG(5) = 25*LOG(5)/LOG(x) \n" ); document.write( "all you need to do now is substitute. \n" ); document.write( "when x = 14.62008869, your formula becomes: \n" ); document.write( "9*LOG(14.6200869)/LOG(5) = 25*LOG(5)/LOG(14.6200869) \n" ); document.write( "solve this using your calculator and you get: \n" ); document.write( "15 = 15, so x = 14.62008869 is good. \n" ); document.write( "remember 14.62008869 is equivalent to 5^(5/3) \n" ); document.write( "when x = .068399038, your formula becomes: \n" ); document.write( "9*LOG(.068399038)/LOG(5) = 25*LOG(5)/LOG(.068399038) \n" ); document.write( "solve this using your calculator and you get: \n" ); document.write( "-15 = -15 \n" ); document.write( "remember .068399038 is equivalent to 5^-(5/3) which is equialent to 1/5^(5/3) \n" ); document.write( "both answers are good. \n" ); document.write( " \n" ); document.write( " |