document.write( "Question 624448: Write an equation of the line tangent to the given circle at the given point.
\n" ); document.write( "\"+x%5E2%2By%5E2=52+\" (-4,6)
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Algebra.Com's Answer #392767 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "Note: Standard Form of an Equation of a Circle is \"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"
\n" ); document.write( "where Pt(h,k) is the center and r is the radius\r
\n" ); document.write( "\n" ); document.write( "Write an equation of the line tangent to the given circle at the given point.
\n" ); document.write( "\"+x%5E2%2By%5E2=52+\" (-4,6) || Center of the circle is (0,0)
\n" ); document.write( "(-4,6)
\n" ); document.write( "(0,0) m = 6/-4 Green Line has slope m = -3/2,
\n" ); document.write( "the Line Tangent at (-4,6) would be perpendicular to the Green with m = 2/3
\n" ); document.write( " y = (2/3)x + b
\n" ); document.write( " 6 = -8/3 + b,
\n" ); document.write( " 26/3 = b , y = (2/3)x + 26/3
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