document.write( "Question 624453: Jomar's father is 9 times as old as he is.
\n" ); document.write( "One year ago, he was 2 years more than 11 times as old as Jomar. Find the age of Jomar and his Father.
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Algebra.Com's Answer #392764 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Jomar = j years old
\n" ); document.write( "Present age of Father = f years old\r
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\n" ); document.write( "\n" ); document.write( "Now
\n" ); document.write( "Jomar's father is 9 times as old as he is
\n" ); document.write( "f=9j.............(1)\r
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\n" ); document.write( "\n" ); document.write( "One year ago
\n" ); document.write( "Jomar was = j-1 years old
\n" ); document.write( "Father was = f-1 years old\r
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\n" ); document.write( "\n" ); document.write( "Then\r
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\n" ); document.write( "\n" ); document.write( "Father was 2 years more than 11 times as old as Jomar
\n" ); document.write( "(f-1)=11(J-1)+2
\n" ); document.write( "f-1=11J-11+2
\n" ); document.write( "f-1=11J-11+2
\n" ); document.write( "f-1=11J-9
\n" ); document.write( "f=11J-9+1
\n" ); document.write( "f=11J-8...............(2)\r
\n" ); document.write( "\n" ); document.write( "Put the value of f from (1) to (2)
\n" ); document.write( "9J=11J-8
\n" ); document.write( "9J-11J=-8
\n" ); document.write( "-2J=-8
\n" ); document.write( "Divide by -2 both sides of the above equation
\n" ); document.write( "-2J/-2=-8/-2
\n" ); document.write( "j=4\r
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\n" ); document.write( "\n" ); document.write( "Put the value of j in (1)
\n" ); document.write( "f=9j.............(1)
\n" ); document.write( "f=9(4)
\n" ); document.write( "f=36\r
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\n" ); document.write( "\n" ); document.write( "Present age of Jomar = j = 4 years old
\n" ); document.write( "Present age of Father = f = 36 years old\r
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