document.write( "Question 624461: can you please help me solve this question 'how old am i if i am 4 times my daughters age today and 7 years earlier i was 11 times her age?' i am not quite sure how to go about solving it thank you.
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Algebra.Com's Answer #392760 by Theo(13342)\"\" \"About 
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let x be your daughter's age now.
\n" ); document.write( "today you are 4 times your daughter's age.
\n" ); document.write( "that means you are 4*x years old.
\n" ); document.write( "7 years ago, you were 11 times her age.
\n" ); document.write( "7 years ago you were 4*x - 7 years old.
\n" ); document.write( "7 years ago, your daughter was x-7 years old.
\n" ); document.write( "you were then 11 times her age which means that:
\n" ); document.write( "4*x - 7 = 11*(x-7)
\n" ); document.write( "solve this equation to get the value of x.
\n" ); document.write( "4x - 7 = 11*(x-7)
\n" ); document.write( "simplify to get:
\n" ); document.write( "4x - 7 = 11x - 77
\n" ); document.write( "add 7 to both sides of this equation to get:
\n" ); document.write( "4x = 11x - 77 + 7 which simplifies to:
\n" ); document.write( "4x = 11x - 70
\n" ); document.write( "subtract 11x from both sides of this equation to get:
\n" ); document.write( "4x - 11x = -70 which simplifies to:
\n" ); document.write( "-7x = -70
\n" ); document.write( "divide both sides of this equation by -7 to get:
\n" ); document.write( "x = 10
\n" ); document.write( "since x is your daughter's age today, she is now 10 years old.
\n" ); document.write( "you are 4 times her age so you are 40.
\n" ); document.write( "7 years ago you were 33.
\n" ); document.write( "7 years ago she was 3
\n" ); document.write( "33 is 11 * 3
\n" ); document.write( "the value of x is good.
\n" ); document.write( "your aqe is now 40.
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