document.write( "Question 624439: what is the answer in this question: Jose is 27 years older than his son. 10 years from now he will be twice as old as his son. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #392740 by vleith(2983)\"\" \"About 
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Let J be Jose's age today and s be his son's age today. You are told
\n" ); document.write( "\"J+=+s+%2B+27\"
\n" ); document.write( "\"%28J%2B10%29+=+2+%2A+%28s%2B10%29\"
\n" ); document.write( "\"J+%2B+10+=+2s+%2B+20\"
\n" ); document.write( "\"J+=+2s+%2B+10\"
\n" ); document.write( "Now you can substitute in the value for J in the first equation at the top into this last one
\n" ); document.write( "\"s+%2B+27+=+2s+%2B+10\" now solve for s
\n" ); document.write( "\"27-10+=+2s+-+s\"
\n" ); document.write( "\"17+=+s\" so his son is 17 today
\n" ); document.write( "Which makes Jose 17+27 = 44\r
\n" ); document.write( "\n" ); document.write( "Check your answer based on what their ages will be in 10 years.
\n" ); document.write( "Is 54 = 2*27
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