document.write( "Question 624150: the present age of a man is three times that of his son six years ago.the age of man was 4 times that of his son.find the ratio of their ages 6 yrs later \n" ); document.write( "
Algebra.Com's Answer #392730 by lwsshak3(11628)\"\" \"About 
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the present age of a man is three times that of his son. Six years ago.the age of man was 4 times that of his son.find the ratio of their ages 6 yrs later
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\n" ); document.write( "let x=son's present age
\n" ); document.write( "3x=father's present age
\n" ); document.write( "..
\n" ); document.write( "6 yrs ago
\n" ); document.write( "(x-6)=son's age
\n" ); document.write( "(3x-6)=father's age
\n" ); document.write( "(3x-6)/(x-6)=4
\n" ); document.write( "3x-6=4x-24
\n" ); document.write( "x=18
\n" ); document.write( "3x=54
\n" ); document.write( "..
\n" ); document.write( "6 yrs later
\n" ); document.write( "(x+6)=son's age
\n" ); document.write( "(3x+6)=father's age
\n" ); document.write( "(3x+6)/(x+6)
\n" ); document.write( "=(54+6)/24
\n" ); document.write( "=60/24
\n" ); document.write( "=5/2
\n" ); document.write( "ratio of father's age/son's age 6 yrs later=5/2\r
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