document.write( "Question 624405: Solve using the substitution method. Show your work. If the system has no solution or an infinite number of solutions, state this.
\n" ); document.write( "-x-3y=.20
\n" ); document.write( "5x+3y=40
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Algebra.Com's Answer #392724 by lawdej(58)\"\" \"About 
You can put this solution on YOUR website!
here is the way
\n" ); document.write( "-x-3y=.20
\n" ); document.write( "5x+3y=40
\n" ); document.write( "take one of the equations as you like
\n" ); document.write( "-x-3y=.20
\n" ); document.write( "x=-3y-.20 substitute this into 5x+3y=40
\n" ); document.write( "5(-3y-.20)+3y=40
\n" ); document.write( "-15y-1+3y=40
\n" ); document.write( "-12y=41
\n" ); document.write( "y=-41/12
\n" ); document.write( "to find value of x substitute y=-41/12 in either equations as you like
\n" ); document.write( "x=-3y-.20=-3(-41/12)-.20
\n" ); document.write( "x=(123-2.4)/14=120.6/12
\n" ); document.write( "x=120.6/14
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