document.write( "Question 624382: Graph the equation (I don't know how to find them)
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document.write( "Identify the vertices of the ellipse.
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document.write( "Identify the co-vertices of the ellipse.
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document.write( "Identify the foci of the ellipse. \n" );
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Algebra.Com's Answer #392705 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Graph the equation (I don't know how to find them) \n" ); document.write( "2x^2+50y^2=50 \n" ); document.write( "Identify the vertices of the ellipse. \n" ); document.write( "Identify the co-vertices of the ellipse. \n" ); document.write( "Identify the foci of the ellipse. \n" ); document.write( "** \n" ); document.write( "2x^2+50y^2=50 \n" ); document.write( "x^2/25+y^2=1 \n" ); document.write( "This is an equation of an ellipse with horizontal major axis with center at the origin (0,0) \n" ); document.write( "Its standard form of equation: x^2/a^2+y^2/b^2=1, a>b \n" ); document.write( "center:(0,0) \n" ); document.write( "a^2=25 \n" ); document.write( "a=5 \n" ); document.write( "Vertices: (0±a,0)=(0±5,0)=(-5,0) and (5,0) \n" ); document.write( ".. \n" ); document.write( "b^2=1 \n" ); document.write( "b=1 \n" ); document.write( "co-vertices: (0,0±b)=(0,0±1)=(0,-1) and (0,1) \n" ); document.write( ".. \n" ); document.write( "c^2=a^2-b^2=25-1=24 \n" ); document.write( "c=√24≈4.9 \n" ); document.write( "Foci: (0±c,0)=(0±4.9,0)=(-4.9,0) and (4.9,0) \n" ); document.write( "see graph below: \n" ); document.write( "y=±(1-x^2/25)^.5 \n" ); document.write( " |