document.write( "Question 624315: Write an equation of the line tangent to the given circle at the given point. I have an idea on how to do it but I often mess up.
\n" ); document.write( " $\"++x%5E2%2By%5E2=13++\"$ (2,3) \n" ); document.write( "

Algebra.Com's Answer #392643 by lwsshak3(11628) $\"\"$ $\"About$

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Write an equation of the line tangent to the given circle at the given point. I have an idea on how to do it but I often mess up.
\n" ); document.write( "x^2+y^2=13 (2,3)
\n" ); document.write( "**
\n" ); document.write( "Equation of a straight line: y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "slope of tangent line=negative reciprocal of slope of line from given point(2,3) to center of circle (0,0)
\n" ); document.write( "slope=∆y/∆x=(3-0)/(2-0)=3/2
\n" ); document.write( "negative reciprocal=-2/3
\n" ); document.write( "Equation of tangent line: y=-2x/3+b
\n" ); document.write( "solve for b using coordinates of given point (2,3)
\n" ); document.write( "3=-2*2/3+b
\n" ); document.write( "b=3+4/3=13/3
\n" ); document.write( "equation of line tangent to circle: y=-2x/3+13/3
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