document.write( "Question 624311: log(1-2x)-2logx = 1-log(2-5x) \n" ); document.write( "

Algebra.Com's Answer #392639 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "log(1-2x)-2logx = 1-log(2-5x)
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document.write( "log(1-2x)-2logx + log(2-5x) = 1
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document.write( " log(1-2x)(2-5x)/x^2 = 1
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document.write( " (1-2x)(2-5x)/x^2 = 10 
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document.write( " (1-2x)(2-5x) = 10x^2 
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document.write( "  2 - 9x + 10x^2 = 10x^2
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document.write( "      2 = 9x
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document.write( "      2/9 = x \n" );
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