document.write( "Question 624311: log(1-2x)-2logx = 1-log(2-5x) \n" ); document.write( "
Algebra.Com's Answer #392638 by oscargut(2103)\"\" \"About 
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log(1-2x)-2logx = 1-log(2-5x)\r
\n" ); document.write( "\n" ); document.write( "log(1-2x)-log(x^2) = log(10)-log(2-5x)\r
\n" ); document.write( "\n" ); document.write( "log((1-2x)/x^2) = log(10/(2-5x))\r
\n" ); document.write( "\n" ); document.write( "(1-2x)/x^2 = 10/(2-5x)\r
\n" ); document.write( "\n" ); document.write( "(1-2x)(2-5x)=10x^2\r
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\n" ); document.write( "\n" ); document.write( "10x^2-9x+2 = 10x^2\r
\n" ); document.write( "\n" ); document.write( "-9x+2 = 0\r
\n" ); document.write( "\n" ); document.write( "x = 2/9\r
\n" ); document.write( "\n" ); document.write( "Answer: x = 2/9\r
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