document.write( "Question 624103: what does it mean to be continuous at x=1, as well as what it means to have discontinuity at x=1. \n" ); document.write( "

Algebra.Com's Answer #392532 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let

be a point in the domain of the function

. Then

is continuous at

if and only if:\r
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\r
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\n" ); document.write( "\n" ); document.write( "So, the statement that

is continuous at

means two things. 1: The value

is an element of the domain set of

and 2:

. The existence of the limit being implied by the fact that it equals something.\r
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\n" ); document.write( "\n" ); document.write( "The statement that

is discontinuous at

means that either the value

is not in the domain set of

(which could be a consequence of the non-existence of the limit).\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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