document.write( "Question 624055: Re question 624022 kindly answered by ewatrrr, I am still confused. Do I have to solve the equation first to find the max nos to input into the calculator so I can see the graph. The first derivative is mentioned. how was that calculated.\r
\n" ); document.write( "\n" ); document.write( "I must admit I am a bit lost with this one.\r
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #392502 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
\n" );
document.write( "Hi
\n" );
document.write( "Re: Do I have to solve the equation first to find the max nos to input into the calculator so I can see the graph.
\n" );
document.write( "using: y = ax^2 +bx + 2 = a(x - (-b/2a))^2...as in Completing the Square...
\n" );
document.write( "one could find that  180/9.8 is the x-value of the maximum point
\n" );
document.write( "and then yes find f(180/9.8) to find the y-value of that maximum point
\n" );
document.write( "Note: the vertex form of a Parabola opening Up(a>0) or Down(a<0)is  where(h,k) is the vertex and line of symmetry is x = h
\n" );
document.write( " The equation is: h=-4.9t^2+180t+2 where h is the height and t is time. 
\n" );
document.write( "Thank you
\n" );
document.write( "h=-4.9t^2+180t+2 
\n" );
document.write( "Yes, one can use a graphing Calculator (using x in place of t)
\n" );
document.write( "As to sizing... 1st derivative tells us Maxmimun is at ~18 (180/9.8) which results in height of 1600+
\n" );
document.write( "Using -100,2000 for y-axis and -60,60 for the x - axis, one can take a look at it
\n" );
document.write( "
\n" );
document.write( " \n" );
document.write( "

\n" );