document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57491>Question 57491</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay here goes nothing..\r<BR>\n" );
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document.write( "The sum of the perimeters of two squares is 40 inches. The sum of their areas is 58 square inches. What are the dimensions of the squares? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39248 by </B><A HREF=/tutors/aboutme.mpl?userid=faceoff57><B>faceoff57(108)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=faceoff57><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=faceoff57><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 58<BR>\n" );
document.write( "9 + 49 = 58   sum of areas<BR>\n" );
document.write( "12 + 28 = 40  sum of perimeters<BR>\n" );
document.write( "one square has a side of 3 inches.<BR>\n" );
document.write( "the other square has a side of 7 inches. </SPAN>\n" );
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