document.write( "Question 623949: A man buys 12 apples every month. If the price fall by 40%, how many more apples would he be able to buy for the exact same amount? \n" ); document.write( "
Algebra.Com's Answer #392442 by Theo(13342)\"\" \"About 
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z equals what he pays each month.
\n" ); document.write( "x equals the price he pays each month.
\n" ); document.write( "he buys 12 apples at a cost of x.
\n" ); document.write( "the equation becomes:
\n" ); document.write( "z = 12x
\n" ); document.write( "the price drops 40%.
\n" ); document.write( "the new price is now .6x per apple.
\n" ); document.write( "he still pays the same each month, so the new equation is:
\n" ); document.write( "z = y*.6x where y is the new number of apples he can now buy.
\n" ); document.write( "since both expressions on the right side of the equations equal z on the left side of the equations, you can set the expressions equal to each other to get:
\n" ); document.write( "12x = y*.6x
\n" ); document.write( "divide both sides of this equation by .6x and you get:
\n" ); document.write( "12x / .6x = y
\n" ); document.write( "x cancels out and you are left with:
\n" ); document.write( "y = 12/.6 which simplifies to:
\n" ); document.write( "y = 20
\n" ); document.write( "if the price drops 40% he can buy 20 apples each month rather than 12 apples each month.
\n" ); document.write( "assume he pays 1.00 per apple.
\n" ); document.write( "12 * 1.00 = 12.00 what he pays each month.
\n" ); document.write( "the price drops by 40% which means the price per apple is now 60 cents.
\n" ); document.write( "20 * 60 cents = 12.00 dollars.
\n" ); document.write( "he pays 12.00 for 12 apples at the old price and he pays 12.00 for 20 apples at the new price.\r
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