document.write( "Question 57480: 1) Solve x2-2x-3>0.
\n" ); document.write( "a. (-3, 1)
\n" ); document.write( "b. (-1, 3)
\n" ); document.write( "c. (- ∞ , -3) U (1, ∞ )
\n" ); document.write( "d. (- ∞ , -1) U (3, ∞ )
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Algebra.Com's Answer #39242 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
1) Solve \"x%5E2-2x-3%3E0\".
\n" ); document.write( "a. (-3, 1)
\n" ); document.write( "b. (-1, 3)
\n" ); document.write( "c. (- infinity , -3) U (1, infinity )
\n" ); document.write( "\"highlight%28d%29\". (- infinity , -1) U (3, infinity )
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\n" ); document.write( "Here's why:
\n" ); document.write( " \"x%5E2-2x-3%3E0\" Find the critical values that make this =0. Factor and solve.
\n" ); document.write( "\"%28x%2B1%29%28x-3%29=0\"
\n" ); document.write( "x+1=0 and x-3=0
\n" ); document.write( "x+1-1=0-1 and x-3+3=0+3
\n" ); document.write( "x=-1 and x=3
\n" ); document.write( "Test the interval (-infinty,-1)
\n" ); document.write( "Test -10 (-10+1)(-10-3) a (-)(-) is a positive. This interval is>0
\n" ); document.write( "Test the interval (-1,3)
\n" ); document.write( "Test 0 (0+1)(0-3) a (+)(-) is a negative. This interval is not >0
\n" ); document.write( "Test the interval (3,infinfty)
\n" ); document.write( "Test 10 (10+1)(10-3) a (+)(+) is a positive. This interval is>0
\n" ); document.write( ":
\n" ); document.write( "Therefore the solution is (-infinity,-1)U(3,infinity)
\n" ); document.write( "Happy Cacluating!!!
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