document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623836>Question 623836</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what are the steps to solve 3y over 2 plus y over 6 equals 35 over 3? It has been awhile since I've worked problems like this and I'm not forsure how to do it? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392370 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what are the steps to solve 3y over 2 plus y over 6 equals 35 over 3? It has been awhile since I've worked problems like this and I'm not forsure how to do it?<BR>\n" );
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document.write( "3y/2+y/6=35/3<BR>\n" );
document.write( "LCD:6<BR>\n" );
document.write( "multiply every term by LCD<BR>\n" );
document.write( "9y+y=70<BR>\n" );
document.write( "10y=70<BR>\n" );
document.write( "divide both sides by10<BR>\n" );
document.write( "y=7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );