document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623818>Question 623818</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of the length of a field is 3x + 4 feet and the measure of the width of the field is x + 7 feet. Find an expression for its perimeter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392368 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The measure of the length of a field is 3x + 4 feet and the measure of the width of the field is x + 7 feet. Find an expression for its perimeter<BR>\n" );
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document.write( "perimeter=twice the length+twice the width<BR>\n" );
document.write( "=2(3x+4)+2(x+7)<BR>\n" );
document.write( "=6x+8+2x+14<BR>\n" );
document.write( "=8x+22 </SPAN>\n" );
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