document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623771>Question 623771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I understand the concept but cannot arrive at the correct answers I think I am messing up the last equation. I keep getting the number of adult tickets is 74 but I know that is not right.  A movie theater charges $7 for adults, $5 for children, and $4 for seniors over age 60. The theater sold 222 tickets and took in $1383. If twice as many adult tickets were sold as the total of children and senior tickets, how many tickets of each kind were sold. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392341 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I understand the concept but cannot arrive at the correct answers I think I am messing up the last equation. I keep getting the number of adult tickets is 74 but I know that is not right.  A movie theater charges $7 for adults, $5 for children, and $4 for seniors over age 60. The theater sold 222 tickets and took in $1383. If twice as many adult tickets were sold as the total of children and senior tickets, how many tickets of each kind were sold.\r<BR>\n" );
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document.write( "Let amount of adults', children's, and seniors' tickets sold be A, C, and S, respectively\r<BR>\n" );
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document.write( "Then:<BR>\n" );
document.write( "A + C + S = 222 ---------- eq (i)<BR>\n" );
document.write( "7A + 5C + 4S = 1,383 ---- eq (ii)<BR>\n" );
document.write( "A = 2(C + S) ---- A = 2C + 2S\r<BR>\n" );
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document.write( "2C + 2S + C + S = 222 ----- Substituting 2C + 2S for A in eq (i)<BR>\n" );
document.write( "3C + 3S = 222<BR>\n" );
document.write( "3(C + S) = 3(74)<BR>\n" );
document.write( "C + S = 74 ------ eq (iii)\r<BR>\n" );
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document.write( "7(2C + 2S) + 5C + 4S = 1,383 ----- Substituting 2C + 2S for A in eq (ii)<BR>\n" );
document.write( "14C + 14S + 5C + 4S = 1,383<BR>\n" );
document.write( "19C + 18S = 1,383 ---- eq (iv)\r<BR>\n" );
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document.write( "C + S = 74 ------ eq (iii)<BR>\n" );
document.write( "19C + 18S = 1,383 ---- eq (iv) <BR>\n" );
document.write( "- 18C – 18S = - 1,332 ------- Multiplying eq (iii) by – 18 ---- eq (v)<BR>\n" );
document.write( "C = 1,383 – 1,332 ------ Adding eqs (iv) and (v)\r<BR>\n" );
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document.write( "C, or amount of children’s tickets sold = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2851%29 ALIGN=MIDDLE  ALT=\"highlight_green%2851%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "51 + S = 74 ----- Substituting 51 for C in eq (iii)<BR>\n" );
document.write( "S = 74 – 51\r<BR>\n" );
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document.write( "S, or amount of seniors’ tickets sold = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2823%29 ALIGN=MIDDLE  ALT=\"highlight_green%2823%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Since A = 2C + 2S, then A = 2(51) + 2(23) ----- A = 102 + 46 \r<BR>\n" );
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document.write( "A, or amount of adults’ tickets sold = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28148%29 ALIGN=MIDDLE  ALT=\"highlight_green%28148%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "I'm sure you can do the check.\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at  MathMadEzy@aol.com </SPAN>\n" );
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